^2log3 = x dan ^3log5 = y maka nilai ^4log15 A. xy + 1 / 2× C. x + y / 2x B. xy + x / 2 D. x + y / 2 E. xy + 1 Itu pilihan ganda yaa

^4log15
= ^3log15 / ^3log4
= [^3log(3×5)] / [^3log(2²)]
= (^3log3 + ^3log5) / (2 . ^3log2)
= (1 + y) / [2 . (1 / ^2log3)]
= (1 + y) / [2 . (1/x)]
= (1 + y) / (2/x)
= [x(1 + y)] / 2
= (xy + x) / 2

Jawaban :
B. (xy + x) / 2