Nilai x yang memenuhi |5×-6| = |18+7×| adalah

NiLai MutLak

|5x - 6| = |18 + 7x|
(5x - 6)² - (18 + 7x)² = 0
▶ A² - B² = (A + B)(A - B)
(12x + 12)(-2x - 24) = 0
12x + 12 = 0 ---> x = -1
-2x - 24 = 0 ---> x = -12

Nilai x yg memenuhi :
x = -1 dan x = -12

kuadratkan kedua ruas
[tex](5x-6)^{2}=(18+7x)^{2}[/tex]
[tex](5x-6)^{2}-(18+7x)^{2}=0[/tex]
[tex][(5x-6)+(18+7x)][(5x-6)-(18+7x)]=0[/tex]
[tex](12x+12)(-2x-24)=0[/tex]
[tex]x_{1}=-1\bigcup x_{2}=-12[/tex]