Bila diketahui : ∆Hf° C2H6(g) = -84,7 kj/mol ∆Hf° O2(g) = 0 kj/mol ∆Hf° CO2(g) = -393,5 kj/mol ∆Hf° H2O(g) = -241,8 kj/mol Tentukan besarnya harga ∆H utk reaksi
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Pertanyaan
Bila diketahui :
∆Hf° C2H6(g) = -84,7 kj/mol
∆Hf° O2(g) = 0 kj/mol
∆Hf° CO2(g) = -393,5 kj/mol
∆Hf° H2O(g) = -241,8 kj/mol
Tentukan besarnya harga ∆H utk reaksi :
2C2H6(g) + 7O2(g) -> 4CO2(g) + 6H2O(g)
∆Hf° C2H6(g) = -84,7 kj/mol
∆Hf° O2(g) = 0 kj/mol
∆Hf° CO2(g) = -393,5 kj/mol
∆Hf° H2O(g) = -241,8 kj/mol
Tentukan besarnya harga ∆H utk reaksi :
2C2H6(g) + 7O2(g) -> 4CO2(g) + 6H2O(g)
1 Jawaban
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1. Jawaban panda2926
ΔH= [4(ΔHf CO2)+6(ΔHf H2O) ]-[2(ΔHf C2H6)]
= [4(-393,5)+6(-241,8)] - [2(-84,7)]
= [(-1.574)+(-1.450,8)] - [-169,4]
= -2.855,4 kj/mol
jadi, ΔH reaksinya -2.855,4 kj/mol