Jawab dengan menggunakan rumus segitiga pascal 1.(p+q)^4 2.(p-q)^6 3.(3p+2q)^5 4.(3a-5b)^3

1). (p+q)^4 =
(p)^4 + 4 (p)^3 (q) + 6(p)^2 (q)^2 + 4(p)(q)^3 + (q)^4
= p^4 + 4p^3 q + 6p^2 q^2 + 4pq^3 + q^4

2). (p-q) ^6 =
(p)^6 + 6 (p)^5 (-q) + 15 (p)^4 (-q)^2 + 20 (p)^3 (-q)^3 + 15(p)^2 (-q)^4 + 6(p)(-q)^5+ (-q)^6
= p^6 - 6p^5 q - 15 p^4 q^2 - 20p^3 q^3 - 15 p^2 q^4 - 6pq^5 - q^6

3). (3p+2q) ^5 =
(3p)^5 + 5(3p)^4 (2q) + 10(3p)^3 (2q)^2 + 10 (3p)^2 (2q)^3 + 5(3p)(2q)^4 + (2q)^5
= 243q^5 + 810p^4 q + 2160 p^2q^3 + 240 pq^4 + 32 q^5

4). (3a-5b) ^3 =
(3a)^3 + 3 (3a)^2 (-5b) + 3 (3a)(-5b)^2 + (-5b)^3
= 27a^2 - 135a^2 b - 225ab^2 - 125b^3