tentukan x dari ^log (1- ^3log 1/27)=2 tentukan x dari log (9^x-4)^1/2=log(81)^x-5 mohon bantuannya.......

LogariTmA



1)  ˣlog(1 - ³log 1/27) = 2
konsep  jika ˣlog a = b --> xᵇ = a
.
x² = 1 - ³log 1/27
x² = 1 - ³log 3⁻³
x² = 1 - (-3)(³log 3)
x² = 1 + 3 = 4
x = √4
x = 2  atau x  = - 2

2) log (9ˣ⁻⁴)¹/² = log (81)ˣ⁻⁵
konsep  jika log aˣ = log bⁿ -->ˣ log a = n log b
..
log (9)¹/²⁽ˣ⁻⁴⁾ = log (9)²⁽ˣ⁻⁵)
1/2(x-4) log 9 = 2(x-5) log 9
1/2 (x-4) = 2(x-5)
1/2 x - 2 = 2x - 10 ....kalikan 2
x - 4 = 4x - 20
x - 4x = 4 -20
-3x = - 16
x = 16/3