bantu kerjakan nomor 2 pakai cara dong, kak terimakasih^^

2.
(x²)^x= x^4x-x²
x^2x = x^4x-x²

2x = 4x - x²
x² + 2x - 4x = 0
x² -2x = 0
x(x-2)= 0
x=0 V x=2

=>>>> D

(x^2)^x = x^(4x - x^2)
x^2x = x^(4x - x^2)

1) x = 1 karena 1^2 = 1^(4 - 1) => 1 = 1

2) x = 0 jika 2x > 0 dan (4x - x^2) > 0
Tetapi krn 2x = 2(0) = 0 maka x = 0 tidak memenuhi ( 0^0 = ?? )

3) x = -1 jika 2x dan (4x - x^2) sama-sama ganjil atau sama2 genap
2x = 2(-1) = -2 => (genap)
4x - x^2 = 4(-1) - (-1)^2 = -4 - 1 = -5 => (ganjil)
jadi x = -1 tidak memenuhi
(-1)^(-2) = (-1)^(-5) => 1 ≠ -1

4) 2x = 4x - x^2
x^2 - 2x = 0
x(x - 2) = 0
x = 0 atau x = 2
Karena berdasarkan surat no 2) x = 0 tdk memenuhi jadi x = 2

HP = {1, 2}