Tolong dibantu tentang vektor

f1x = 16 . cos 60= 16 . 1/2 = 8
f1y = 16. sin 60 = 16 .1/2 akar 3 = 8 akar 3
f2x= 20 . cos 30 = 20 . 1/2 akar 3 = 10 akar 3
f2y= 20 . sin 30=20 .1/2 = 10
sigma fx = 8 + 10 akar 3
= 8 + 17
= 35
sigma fy = 8 akar 3 + 10
13,6 + 10
= 23,6

resultan = akar 35^2 + 23,6 ^2
= akar 1225 + 556,96
= akar 1781,96
= 42,21