Matematika

Pertanyaan

tentukan hasil integral dari:
a. int sin^6 x cos x dx
b. int -2 smpai 3 (4x-3) dx

2 Jawaban

  • a. -cos(pangkat 6)x sinx + c
    semoga benar
  • a) int (sin^6 x cos x) dx

    misal : u = sin x => du = cos x dx

    int sin^6 x cos x dx
    = int u^6 du
    = 1/7 u^7 + C
    = 1/7 sin^7 x + C

    b) int (4x - 3) dx
    = 2x^2 - 3x | (batas -2 sampai 3)
    = (2.3^2 - 3(3)) - (2 (-2)^2 - 3(-2))
    = (18 - 9) - (8 + 6)
    = 9 - 14
    = -5

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