Diketahui : f(x) = x² + 6x + 5 g(x) = √x+4 h(x) = x² - 5x + 1 Ditanya : Rumus fungsi (g o f o h) (x) adalah keterangan: o = bundaran

[tex](g\circ f\circ h)(x) \\ g(f(h(x))) \\ g(f(x^2-5x+1)) \\ g((x^2-5x+1)^2+6(x^2-5x+1)+5) \\ g(x^4+25x^2+1-10x^3+2x^2-10x+6x^2-30x+6+5) \\ g(x^4-10x^3+33x^2-40x+12) \\ \sqrt{(x^4-10x^3+33x^2-40x+12)+4} \\ \sqrt{x^4-10x^3+33x^2-40x+16} \\ \sqrt{(x-4)^2(x-1)^2} \\ (x-4)(x-1) \\ x^2-5x+4[/tex]