a log12 + a log27 per a log18= A.0 B.1 C.2 D.3 E.4

Materi Logaritma[tex] \frac{^a \log 12 + ^a \log 27}{^a \log 18} = \frac{^a \log (12.27)}{^a \log 18} \\ = \frac{^a \log (324)}{^a \log 18} \\ = ^{18} \log 324 = ^{18} \log 18^2 = 2 [/tex]

(alog 12+alog 27)/alog 18
= (alog(12 × 27))/alog 18
= alog 324 × 18log a
= 18log 324
= 2
isinya c. 2