tolong di jelaskan cara kerja nya

Penyelesaian:

[tex]( \frac{4}{2^3x+1})^3 = \sqrt[4]{ \frac{1}{16} } [/tex]
[tex]( \frac{4^3}{2^(3x+1)(3)}) = \sqrt[4]{ \frac{1}{2^4} } [/tex]
[tex]( \frac{64}{2^9x+3}) = \frac{1}{2} [/tex]
[tex]128 = 2^9x+3[/tex]
[tex]2^7 = 2^9x+3[/tex]
7 = 9x + 3
9x = 4
x = 4/9