fungsi invers dari: f(x)=x-3/2x+1

Penyelesaian:

f(x) = [tex] \frac{x-3}{2x+1} [/tex]
y = [tex] \frac{x-3}{2x+1} [/tex]
y(2x+1) = x - 3
2xy + y = x - 3
2xy - x = -y - 3
x(2y - 1) = -y - 3
x = [tex] \frac{-y - 3}{2y - 1} [/tex]
y = [tex] \frac{-x - 3}{2x - 1} [/tex]

f(x)^-1 = [tex] \frac{-x - 3}{2x - 1} [/tex]