kak tolong dijawab yahh dan jelaskan bagaimna caranya ini menyangkut persamaan eksponen kak..

Penyelesaian:

4. [tex]3^( \frac{x^2-4x-5}{3x-1}) = 1 [/tex]
[tex]3^0 = 1^0[/tex]
1 = 1

[tex] \frac{x^2-4x-5}{3x-1} = 0[/tex]
x² - 4x - 5 = 0
(x - 5)(x + 1) = 0
x = 5 atau x = -1

5. [tex]3^(x^2-x-9) = \frac{1}{27} [/tex]
[tex]3^(x^2-x-9) = 3^-3[/tex]
x² - x - 9 = -3
x² - x - 6 = 0
(x - 3)(x + 2) = 0
x = 3 atau x = -2

6. [tex]( \frac{4}{2^3x+1})^3 = \sqrt[4]{ \frac{1}{16} } [/tex]
[tex]( \frac{4^3}{2^3x+1(3)}) = \sqrt[4]{ \frac{1}{2^4} } [/tex]
[tex] \frac{4^3}{2^9x+3} = \frac{1}{2} [/tex]
[tex]128 = 2^9x+3[/tex]
[tex]2^7 = 2^9x+3[/tex]
7 = 9x + 3
9x = 4
x = 4/9