tolong dibantu ya ......
Matematika
AmyCarina
Pertanyaan
tolong dibantu ya ......
1 Jawaban
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1. Jawaban Wiraa
Penyelesaian:
[tex]A = \left[\begin{array}{cc}-3&p\\0&5\end{array}\right] [/tex]
[tex]B = \left[\begin{array}{cc}3&4\\0&2\end{array}\right] [/tex]
AB = BA
[tex]\left[\begin{array}{cc}-3&p\\0&5\end{array}\right] . \left[\begin{array}{cc}3&4\\0&2\end{array}\right] = \left[\begin{array}{cc}3&4\\0&2\end{array}\right] . \left[\begin{array}{cc}-3&p\\0&5\end{array}\right] [/tex]
[tex]\left[\begin{array}{cc}-9&2p-12\\0&10\end{array}\right] = \left[\begin{array}{cc}-9&3p+20\\0&10\end{array}\right] [/tex]
2p - 12 = 3p + 20
p = -32 (E).