Matematika

Pertanyaan

tolong dibantu ya ......
tolong dibantu ya ......

1 Jawaban

  • Penyelesaian:

    [tex]A = \left[\begin{array}{cc}-3&p\\0&5\end{array}\right] [/tex]
    [tex]B = \left[\begin{array}{cc}3&4\\0&2\end{array}\right] [/tex]

    AB = BA

    [tex]\left[\begin{array}{cc}-3&p\\0&5\end{array}\right] . \left[\begin{array}{cc}3&4\\0&2\end{array}\right] = \left[\begin{array}{cc}3&4\\0&2\end{array}\right] . \left[\begin{array}{cc}-3&p\\0&5\end{array}\right] [/tex]
    [tex]\left[\begin{array}{cc}-9&2p-12\\0&10\end{array}\right] = \left[\begin{array}{cc}-9&3p+20\\0&10\end{array}\right] [/tex]
    2p - 12 = 3p + 20
    p = -32 (E).