4 log ( 4.32 ) ? 7 log ( 49/343 ) ?
Matematika
awmukomuko
Pertanyaan
4 log ( 4.32 ) ?
7 log ( 49/343 ) ?
7 log ( 49/343 ) ?
1 Jawaban
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1. Jawaban mhaidarfh02
4log (4.32) = 4log 4 + 4log32
= 1 + 4log 4².2
= 1 + 2.4log 4 + 4log 2
= 1 + 2 + 1/2
= 3 1/2
7log (49/343) = 7log 49 - 7log 343
= 7log 7² - 7 log 7³
= 2 - 3
= -1