Bantu di soal ini ya, soalnya ada di gambar :D trus gunakan metode Determinan, thank youuuu..

Ya, gini aja,
[tex]\displaystyle x=\frac{\left|\begin{array}{ccc}9&-3&2\\-9&4&-3\\12&-2&5\end{array}\right|}{\left|\begin{array}{ccc}1&-3&2\\2&4&-3\\3&-2&5\end{array}\right|}=\frac{180+108+36-(96+54+135)}{20+27-8-(24+6-30)} \\ x=\frac{39}{39}=1[/tex]

[tex]\displaystyle y=\frac{\left|\begin{array}{ccc}1&9&2\\2&-9&-3\\3&12&5\end{array}\right|}{\left|\begin{array}{ccc}1&-3&2\\2&4&-3\\3&-2&5\end{array}\right|}=\frac{-45-81+48-(-54-36+90)}{20+27-8-(24+6-30)} \\ y=\frac{-78}{39}=-2[/tex]

[tex]\displaystyle z=\frac{\left|\begin{array}{ccc}1&-3&9\\2&4&-9\\3&-2&12\end{array}\right|}{\left|\begin{array}{ccc}1&-3&2\\2&4&-3\\3&-2&5\end{array}\right|}=\frac{48+81-36-(108+18-72)}{20+27-8-(24+6-30)} \\ z=\frac{39}{39}=1[/tex]