((3×-1)²)²=a×⁴+b׳+cײ-9×+1
Matematika
dijah41
Pertanyaan
((3×-1)²)²=a×⁴+b׳+cײ-9×+1
1 Jawaban
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1. Jawaban Murva
(3x-1)²)² = (3x-1)⁴
(3x-1)⁴ = ax⁴ + bx³+cx².....
Aturan segitiga pasal
(A-B)⁴ 》1,4,6,4,1
(3x-1)⁴ = (3x)⁴ - (3x)³×1 +(3x)²-3x+1
= 81x⁴ - 27x³ +9x²-3x+1
81x⁴ =ax⁴
- 27x³ = bx³
9x²=cx²
Jadi a= 81 , b =-27 , c = 9