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PLTU berdaya 200 MW menerangi kota selama 1 jam ,berapa kilojoule energi yg di jasilkan.tolong pakai caranya ,diket dit,jwb

2 Jawaban

  • P = 200 MWatt = 200 x 10^6 Watt
    t = 1 jam = 3600 detik
    tanya W = ...?

    P = W / t
    P = 200 x 10^6 / 3600
    P = 5,5 x 10 4 Joule = 550 kJoule


  • P = 200 MW = 200×10⁶ = 2×10⁸ W
    t = 1 jam = 3600 s
    W = __?

    Energi
    W = P t
    W = (2×10⁸ W) (3600 s)
    W = 7,2×10¹¹ J
    W = 7,2×10⁸ kJ ← jwb

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